二分查找
二分查找
public int binarySearch(int[] nums, int target) {
if (nums == null || nums.length == 0) {
return -1;
}
int start = -1, end = nums.length;
int mid;
while (start + 1 < end) {
// avoid overflow when (end + start)
mid = start + (end - start) / 2;
if (nums[mid] < target) {
start = mid;
} else {
end = mid;
}
}
if (end == nums.length || nums[end] != target) {
return -1;
} else {
return end;
}
}